by Dr. Carol JVF Burns (website creator)
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This section gives a useful application of synthetic division and the division algorithm,
called the Remainder Theorem or the Polynomial Remainder Theorem.

The Remainder Theorem provides an efficient way to evaluate a polynomial at a given number:
that is, to find $\,P(c)\,$ for a given polynomial $\,P(x)\,$ and a given real number $\,c\,$.

How?   Just divide $\,P(x)\,$ by $\,x - c\,$ and then take the remainder!
After the example below is a precise statement of the Remainder Theorem, and why it works.


Let $\,P(x) = 2x^5 - 3x^4 + 5x - 7\,$.   Find $\,P(4)\,$.


Divide $\,P(x)\,$ by $\,x-4\,$, using synthetic division.
Since we're dividing by $\,x - 4\,$, the number $\,4\,$ goes in the little box:

The remainder is $\,1293\,$, so $\,P(4) = 1293\,$.
How easy is that!?

Let's check this result with old-fashioned function evaluation:

$\displaystyle \begin{align} \cssId{s17}{P(4)\ } &\cssId{s18}{= 2\cdot4^5 - 3\cdot4^4 + 5\cdot 4 - 7}\cr &\cssId{s19}{= 2\cdot1024 - 3\cdot256 + 20 - 7}\cr &\cssId{s20}{= 1293} \end{align} $

Notice that function evaluation requires powers (like $\,4^5\,$),
whereas the Remainder Theorem requires only multiplication and addition.

the Remainder Theorem finding $\,P(c)\,$ for a polynomial $\,P\,$
Let $\,P(x)\,$ be a polynomial, and let $\,c\,$ be a real number.
Then, $\,P(c)\,$ is the remainder when $\,P(x)\,$ is divided by $\,x - c\,$.


By the division algorithm, there exist unique polynomials $\,Q(x)\,$ (the quotient) and $\,R(x)\,$ (the remainder) such that $$\cssId{s30}{P(x) = Q(x)(x-c) + R(x)}\,,$$ where either

If $\,R(x)\,$ is zero, then it's a number—a constant.
If $\,R(x)\,$ has degree zero (which is the only degree less than $\,1\,$), then it is a constant.
So, in both cases, $\,R(x)\,$ is a constant—it doesn't depend on $\,x\,$ at all.
To reflect this, give $\,R(x)\,$ a simpler name, $\,R\,$: $$\cssId{s38}{P(x) = Q(x)(x-c) + R}$$ Evaluating $\,P\,$ at $\,c\,$ gives: $$ \cssId{s40}{P(c)} \quad \cssId{s41}{= \quad Q(c)(c - c) + R} \quad \cssId{s42}{= \quad Q(c)\cdot 0 + R} \quad \cssId{s43}{= \quad 0 + R} \quad \cssId{s44}{= \quad R}$$

Master the ideas from this section
by practicing the exercise at the bottom of this page.

When you're done practicing, move on to:
‘trapping’ the roots of a polynomial;
the confinement theorem

On this exercise, you will not key in your answer.
However, you can check to see if your answer is correct.